what is the ratio of volume of 1g H2 to the volume of 16g CH4 at STP?
A. 1:2
B. 2:1
plz guide the right answer with explanation.
IMMEDIATELY PLZ
Answers
The ratio of volume of 1g H2 to the volume of 16g CH4 at STP is 1:2 .
Concept:
- We can compare any two gases using combined gas law.
- Combined gas law is derived from ideal gas law.
- Ideal gas law states that , ratio of product of pressure and volume with temperature is constant.
PV/T= constant
Mathematical form,
PV=nRT
Where,
P= pressure
V= Volume
n= No.of moles
T= Temperature
R= Universal gas constant
using this above ideal gas law we can derive combined gas law, illustrated as follows..
P1V1/n1T1 = P2V2/ n2T2
were,
P1,P2= pressure of gas 1 and 2 , respectively
V1 and V2 = volumes
T1 and T2 = temperature
n1 and n2= moles.
Calculation:
moles of H2= mass / molecular mass
= 1/2 =0.5
moles of CH4 = mass /molecular mass
= 16/16 = 1
At, STP
that means that both gases are having similar conditions,
so, we can rewrite combined gas law as follows..
V1/n1= V2/n2
now,
V1/V2 = n1/ n2
=0.5/1
=1/2
Hence, The ratio of volume of 1g H2 to the volume of 16g CH4 at STP is 1:2 .
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