Question

What is the ratio of volumes occupies by 8grams of methane and 2.5 moles of co2 at NTP

Answer 1

Given

• 8 grams of $CH_4$

• 2.5 moles of $CO_2$

To Find

Ratio of their moles at NTP.

Concept

At NTP, 1 mole of all the gas occupies the same volume V and V = 22.4 litre.

Solution

Molar mass of $CH_4$ = 16 gram.

Hence, number of moles in 8 gram $CH_4$ = $\frac{8}{16}$ = $\frac{1}{2}$ =

Now,

Let volume of 1 mole of $CH_4$ = Volume of $CO_2$ = V.

=> Volume of $\frac{1}{2}$ mole $CH_4$ = $\frac{V}{2}$

Hence, the ratio of volume of $\frac{1}{2}$ mole $CH_4$ and 1 mole $CO_2$ = $\frac{ \frac{v}{2} }{v}$ = $\frac{1}{2}$ Ans.