Question

what is the ratio of weights of o2 and so2 the mixture which contain equal number of molecules of each gas?
A.1:8
B.8:1
C.1:2
D.2:1
Detailed answer please...​

Answer 1

Answer: C) 1:2

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

Thus 1 mole of $O_2$ and 1 mole of $SO_2$ contains equal number of molecules i.e $6.023\times 10^{23}$ molecules.

Now 1 mole of $O_2$ weighs 32 g

1 mole of $SO_2$ weighs = 64 g

Thus ratio of weights of $O_2$ and $SO_2$ the mixture which contain equal number of molecules of each gas is $\frac{32}{64}=\frac{1}{2}$