What is the ratio radius of proton & alpha particle fired in a magnetic field perpendicular with equal momentum?
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Answer:
A proton and an alpha particle enter the same magnetic field which is perpendicular to their velocity and have the same kinetic energy.
Given,
m α =4m p
q α =2q p
The radius of the circular path is given by
r= qBqB2m . . . . . . . .(1)
r∝ qm
r a
r p = m a
m pm . q p
q a
r α
r p = 4m p
m p . qp
2q p
r a
r p=2 41
r α
r p =1
r p :r α =1:1
Explanation:
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Answered by
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