what is the reaction called when oxidation and reduction take place simultaneously ?explained with one example.
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Oxidation is supposed to occur in these conditions, loss of electrons loss of H, addition of O or increase in oxidation state. On the other hand, reduction is the reverse of all these above mentioned conditions. When one specie in a reaction is supposed to loss electron then the other specie must be ready to accept. When an oxidizing substance oxidize another substance then that oxidizing substance donate electro-negative atom or radical to the other substances or accepts electro-positive atom or radical. As a result electro-negative part of that substance increases. On the other hand as the oxidizing substances releases electronegative part or accepts positive part, it is reduced. Both these changes happen in the same reaction.
It can be explained by the following reaction:
For e.g. If we add stannous chloride solution to the yellow solution of ferric chloride then light green ferrous chloride solution and stannic chloride solution are produced.
2FeCI3 (aq) + SnCI2 (aq) → 2FeCl2(aq) + SnCI4 (aq)
Before the reaction, 3Cl atoms were attached with each iron atom. After reaction only two chlorine atoms are attached. That is one negative chlorine atom is released. Therefore, reduction of FeCl3 happened or this reactor on the other hand, before reaction two chlorine atoms where attached with each atom of tin (stannum). Due to the above reaction the number of chlorine attached to tin atom increases to four. That is, oxidation of SnCl2 has taken place. There in this reaction oxidation of one substance and reduction of another substance have taken place; i.e. oxidation-reduction took place simultaneously.
Oxidation and reduction are two parts of any reaction which performs gaining and releasing of electron. For e.g. by oxidation reduction process between sodium atom and chlorine atom, NaCl is produced. It can be shown as follow:
Cl2 → 2Cl Formation of Cl atom from Cl2 molecule.
2Na → 2Na+ + 2e Oxidation (Na is reducing agent)
2Cl + 2e →2Cl
–
Reduction (Cl is oxidants)
2Na + Cl2 → 2(Na+ + Cl–) → 2Na+Cl– (Oxidation-Reduction)
That is oxidation-reduction takes place simultaneously.
It can be explained by the following reaction:
For e.g. If we add stannous chloride solution to the yellow solution of ferric chloride then light green ferrous chloride solution and stannic chloride solution are produced.
2FeCI3 (aq) + SnCI2 (aq) → 2FeCl2(aq) + SnCI4 (aq)
Before the reaction, 3Cl atoms were attached with each iron atom. After reaction only two chlorine atoms are attached. That is one negative chlorine atom is released. Therefore, reduction of FeCl3 happened or this reactor on the other hand, before reaction two chlorine atoms where attached with each atom of tin (stannum). Due to the above reaction the number of chlorine attached to tin atom increases to four. That is, oxidation of SnCl2 has taken place. There in this reaction oxidation of one substance and reduction of another substance have taken place; i.e. oxidation-reduction took place simultaneously.
Oxidation and reduction are two parts of any reaction which performs gaining and releasing of electron. For e.g. by oxidation reduction process between sodium atom and chlorine atom, NaCl is produced. It can be shown as follow:
Cl2 → 2Cl Formation of Cl atom from Cl2 molecule.
2Na → 2Na+ + 2e Oxidation (Na is reducing agent)
2Cl + 2e →2Cl
–
Reduction (Cl is oxidants)
2Na + Cl2 → 2(Na+ + Cl–) → 2Na+Cl– (Oxidation-Reduction)
That is oxidation-reduction takes place simultaneously.
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Answer:
Here's your answer...
Explanation:
- the the process in which oxidation and reduction oca simultaneously is called redox reaction.
- oxidation is the loss of electrons or an increase in oxidation state by a molecule atom or ion.
- reduction is the gain of electrons or decrease in oxidation state by a molecule atom or iron.
- for example : 2H2S + SO2 ---> 3S + 2H2O
- in this reaction SO2 is reduced and H2S is oxidised.
Hope this helps you...
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