Chemistry, asked by srivarsha3557, 1 year ago

What is the reagent used for golden spangle test in lead?

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Answered by pramoddubey08
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Golden rain demonstration is made by combining two colorless solutions, potassium iodide solution and Lead(II) nitrate solution at room temperature to form yellow precipitate. During the chemical reaction, golden particles gently drop from the top of erlenmeyer flask to bottom, similar to watching the rain through a window. The golden rain chemical reaction demonstrates the formation of a solid precipitate. The golden rain experiment involves two soluble ionic compounds, potassium iodide (KI) and lead(II) nitrate (Pb(NO3)2). They are initially dissolved in separate water solutions, which are each colorless. When mixed, as the lead from one solution and the iodide from the other combine to form lead(II) iodide (PbI2), which is insoluble at low temperature and has a golden bright yellow color. Although this is a reaction solely of the dissociated ions in solution, it is sometimes written as a double displacement reaction:[1]

Pb(NO3)2 + 2KI → 2KNO3 + PbI2
At higher temperature, this substance easily re-dissolves by dissociation to its colorless ions.

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