What is the reduced form of the function F= X(X+Y)+X(X'+Y)
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Answer:
x is reduced........
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The reduced form of the function F= X(X+Y)+X(X'+Y) is X
F= X(X+Y)+X(X'+Y) (Given)
Solving as per various laws -
F = (X.X) + (X.Y) + (X.X') + (X.Y) ( Distributive law )
F = X + (X.Y) + 0 + (X.Y) ( Idempotent law )
= X + (X.Y) ( Idempotent law )
= X ( 1+Y) ( Identity law )
= X ( Annulment law )
Thus, the reduces value is X.
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