Question

what is the refractive index of second medium with respect to first medium if light moves through the first medium with a velocity 5×10^8 m/s which change to 3. 25×^8 m/s in second medium​

Answer 1

Explanation:

v1 = 5 × 10^8

v2 = 3.2 × 10^8

if n is refractive index then,

n = v1/v2

n = (5×10^8)/3.25×10^8

n = 5/3.25

n = 1.53