Question

what is the relation between delta H and Delta e

Answer 1

∆H=∆U/∆E +∆n(g)RT this is the relation . And here ∆U is always same as ∆E

Answer 2

The relation between enthalpy and internal energy is $\Delta H=\Delta U+\Delta n_g\times RT$

Explanation:

$\Delta H=\Delta U+P\Delta V$

also $PV=nRT$

thus $P\Delta V=\Delta n_g\times RT$

$\Delta H=\Delta U+\Delta n_g\times RT$

where,

$\Delta H$ =  enthalpy of the reaction

$\Delta U$= internal energy of the reaction

$\Delta n_g$ = change in the moles of the reaction = Moles of product - Moles of reactant

R = gas constant

T = temperature

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