what is the relation between electric field intensity and potential?
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Answer:
The relation is very simple. Electric field intensity is equal to the negative of rate of change of potential with respet to the distance or it can be defined as the negative of the rate of derivative of potential difference, V with respect to r,
E = - dV/dr.
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Answer:
F=1/4pir q1q2/r2
Explanation:
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