Question

what is the relation between mole fraction and molality?

please can anyone explain it in a simple way....

Answer 1

  XA = n/N+n and XB = N/N+n

 

 

  XA/XB = n/N = Moles of solute/Moles of solvent = wA/mB/wB×mA

 

 

  XA×1000/XB×mB = wA×1000/wB×mA = m

 

 

  or XA×1000/(1–XA) = m

Answer 2

RELATION BETWEEN, MOLARITY, MOLALITY AND DESNITY-m=1000M/(1000d-molecular mass of solute)
D=M [ (1/m) + (molecular mass of solute/1000) ]
The relation between molarity, density and percentage of solute- M= (%×d×10)/(molecular mass of solute)
Relation between mole fraction and MOLALITY- m= [X(a)/X(b)]×1000/molecular mass of solutesolute