Question

what is the relation between mole fraction and molality?

please can anyone explain it in a simple way....

Answer 1

Hey mate!!!

▶ Here is ur answer ⬇⬇⬇

Molality:

 

It is defined as the number of the moles of the solute present in 1 kg of the solvent, It is denoted by m.

 

 

  Molality (m) = Number of moles of solute/Number of kilo/grams of the solvent

 

Let wA grams of the solute of molecular mass mA be present in wB grams of the solvent, then

 

  Molality (m) = wA/mA×wB × 1000

 

Relation between mole fraction and Molality:

 

 

  XA = n/N+n and XB = N/N+n

 

 

  XA/XB = n/N = Moles of solute/Moles of solvent = wA/mB/wB×mA

 

 

  XA×1000/XB×mB = wA×1000/wB×mA = m

 

 

  or XA×1000/(1–XA) = m

HOPE IT HELPS.

Answer 2

hello mate

I am here with your answer

solution for relation between mole fraction and molaity is
as

XA = n/N+n and XB = N/N+n    

Moles of solute/Moles of solvent = wA/mB/wB×mA    

 XA/XB = n/N =

XA×1000/XB×mB = wA×1000/wB×mA =m

I hope helps you