Question

what is the relation between n(A),n(B),n(A intersection B)and n(A union B).?..
question is related to chapter sets...​

Answer 1

n(AUB) =n(A)+n(B)-n(A intersection B)

Answer 2

The relation between n (A), n (B), n (A ∩ B) and n (A U B) can be given as follows :

n (A U B) = n (A) + n (B) - n (A ∩ B)

- Here, n (A), n (B), n (A ∩ B) and n (A U B) is the number of elements in set A, set B, intersection of A & B and union of A & B respectively

- Here, the union of A & B is equal to the sum of elements of A and elements of B and then subtracting the intersection of A & B from it.

- Intersection is subtracted so that the elements which are common to both A and B should not repeat.

- This relation can also be represented as follows :

n (A ∩ B) = n (A) + n (B) - n (A U B)