What is the relation between solubility and solubility product for AgCl?
Derive the relation too
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agcl=ag+ + cl-
let initial moles =s
after dissociation ag+ =s and cl- =s
keq=[ag+][cl-]/[agcl]
keq [agcl]=[ag+][cl-]
ksp=[ag+][cl-]
ksp=[s][s]
ksp=s^2
s=underroot ksp
this is the answer
let initial moles =s
after dissociation ag+ =s and cl- =s
keq=[ag+][cl-]/[agcl]
keq [agcl]=[ag+][cl-]
ksp=[ag+][cl-]
ksp=[s][s]
ksp=s^2
s=underroot ksp
this is the answer
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