What is the relation of coefficients, m, n p and q of the following reaction when balanced?
mX2 + nY, → pX Yt + qX,Y,
(A) 2 (m+n) =p(s + t) = q (u + v)
(B) 2 (m + n) =p(s + t) + q (u + v)
(C) 2m + ps +qu = 2n + pt + qy
(D) m+n=p+q
Answers
Answer:
NX is produced by the following step of reactions:
M+X
2
⟶MX
2
3MX
2
+X
2
⟶M
3
X
8
M
3
X
8
+N
2
CO
3
⟶NX+CO
2
+M
3
O
4
How much M (metal) is consumed to produce 206gm of NX?
(Take atomic weight of M=56,N=23,X=80)
Step-by-step explanation:
Correct option is
A
aαv
3
The relation between the timet and position x for a particle moving on the x-axis is given by
t=px
2
+gx
Differentiate with respect to time,
dt
dt
=
dt
d(px
2
)
+
dt
d(qx)
1=2px
dt
dx
+q
dt
dx
. . . .. .(1)
We know that, velocity v=
dt
dx
Equation (1) becomes
1=2pxv+qv
x=
2pv
1−qv
. . . . . .(2)
Differentiate with respect to time again
dt
d(1)
=2p
dt
d(xv)
+q
dt
dv
0=2p(x
dt
dv
+v
dt
dx
)+q
dt
dv
2p(xa+v.v)+qa=0 (a=
dt
dv
)
2pxa+2pv
2
+qa=0
2p
2pv
1−qv
a+2pv
2
+qa=0 (from equation 2)
(
v
1−qv
)a+qa=−2pv
2
a(1−qv+qv)=−2pv
3
a=−2pv
3
a∝v
3
The correct option is A.