Question

What is the relationship between de Broglie's wavelength and momentum
h
(a) 2 = h +p
(b) 2 =
(c) 2 =h xp?
P
(d) 2 =
?
(​

Answer 1

Answer:

The relationship between momentum and wavelength for matter waves is given by p = h/λ, and the relationship energy and frequency is E = hf. The wavelength λ = h/p is called the de Broglie wavelength, and the relations λ = h/p and f = E/h are called the de Broglie relations.