what is the relationship between the standard Gibbs energy change and the equilibrium constant of the reaction
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15
Answer:
the relation is given as follows
Explanation:
∆G=∆G°+RT lnK
∆G is Gibbs energy for a reaction
∆G° is standard Gibbs energy
K is equilibrium constant
at equilibrium, ∆G=0
therefore, ∆G°= - RT lnK
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If the products and reactants are in their standard states and ΔG° < 0, then Kp > 1, and products are favored over reactants when the reaction is at equilibrium. Conversely, if ΔG° > 0, then Kp < 1, and reactants are favored over products when the reaction is at equilibrium .
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