Question

What is the relative acceleration between electron and proton due to mutual attraction between electron and a proton when they are 1.6 Angstroms apart?​

Answer 1

Explanation:

Step 1: Force between electron and proton

Distance between electron and proton, r=1

A

˚

=10

−10

m

From Coulomb's law, F=

4πϵ

0

1

r

2

e

2

=

(10

−10

m)

2

9×10

9

×(1.6×10

−19

C)

2

=2.3×10

−8

N

Step 2: Acceleration of proton and electron

From newton's law, F=ma

Acceleration of electron =

m

e

F

=

9×10

−31

kg

2.3×10

−8

N

=2.5×10

22

m/s

2

Acceleration of proton =

m

p

F

=

1.66×10

−27

kg

2.3×10

−8

N

=1.4×10

19

m/s

2