What is the remainder if (32^32 + 32) is divided by 33?
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Step-by-step explanation:
33³²=1(mod 33). ( using fermat's first theorem)
32=32(mod. 33)
adding both these equations.
33³²+32=1+32(mod33)
33³²+32=33(mod 33)
33³²+32=0(mod 33). since remainder 33 is exactly divisible by divisor
33
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