Question

What is the remainder obtained on dividing
p(x)=x^4-ax^3-3x-a by x-a
​

Answer 1

Answer:

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Step-by-step explanation:

Using basics of remainder theorem, remainder of f(x) when divided with

(x-a) will be f(a).

So from the above data, f(-1) = 6 and f(1) = 0.

Substituting it, 3(-1)^4-a(-1)^3+2a(-1)^2-(-1)-b = 6

i.e. 3+a+2a+1-b = 6 => 3a - b = 2

Also 3(1)^4-a(1)^3+2a(1)^2-(1)-b = 0

i.e. 3-a+2a-1-b = 0 => a - b = -2

Solving these two equations, we can get a = 2, b = 4.