What is the remainder obtained when the polynomial p(x)=x^7+9x^5+5x^3+x-1
divided by x-1
Answers
Answered by
2
Answer:
Step-by-step explanation:
X=1
1+9+5+1-1
16-1
15 is the answer
Answered by
1
Answer:
a. 15
Step-by-step explanation:
As per remainder theorem, the remainder obtained when the polynomial is divided by will be x-1 same as the value of the polynomial at
As per remainder theorem, the remainder obtained when the polynomial is divided by will be x-1 same as the value of the polynomial at x=1
As per remainder theorem, the remainder obtained when the polynomial is divided by will be x-1 same as the value of the polynomial at x=1 P(1)=1^{7}+9\times(1)^{5}+5\times(1)^{3}+1 -1=15
As per remainder theorem, the remainder obtained when the polynomial is divided by will be x-1 same as the value of the polynomial at x=1 P(1)=1^{7}+9\times(1)^{5}+5\times(1)^{3}+1 -1=15 thus remainder when x^{7}+9x^{5}+5x^{3}+x-1 is divided by x-1~is~15 .
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