Math, asked by mnakkq, 9 months ago

What is the remainder obtained when the polynomial p(x)=x^7+9x^5+5x^3+x-1
divided by x-1​

Answers

Answered by anup15416668nnRitik
2

Answer:

Step-by-step explanation:

X=1

1+9+5+1-1

16-1

15 is the answer

Answered by brabo32
1

Answer:

a. 15

Step-by-step explanation:

As per remainder theorem, the remainder obtained when the polynomial is divided by will be x-1 same as the value of the polynomial at

As per remainder theorem, the remainder obtained when the polynomial is divided by will be x-1 same as the value of the polynomial at x=1

As per remainder theorem, the remainder obtained when the polynomial is divided by will be x-1 same as the value of the polynomial at x=1 P(1)=1^{7}+9\times(1)^{5}+5\times(1)^{3}+1 -1=15

As per remainder theorem, the remainder obtained when the polynomial is divided by will be x-1 same as the value of the polynomial at x=1 P(1)=1^{7}+9\times(1)^{5}+5\times(1)^{3}+1 -1=15 thus remainder when x^{7}+9x^{5}+5x^{3}+x-1 is divided by x-1~is~15 .

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