Question

What is the remainder R when the polynomial p(x) is divided by (x-5)?​

Answer 1

Answer:

x

2

−1→(x+1)(x−1)

x

2

−1[P(x)][Q(x)]→R=ax+b

⇒(x+1)(x−1)⋅xQ(x)+ax+b=P(x)

whenx=−1→1=−a+b

whenx=1→2=a+b

solving the above equations we get, a=

2

1

,b=

2

3

Remainder =ax+b⇒

2

1

x+

2

3

=

2

1

(x+3)