What is the remainder when 1! + 2! + 3! + … + 50! is divided by 12?
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1+2+6+(remaining all numbers of are divisible by 12)
[so their sum is alsoo divisible by 12 ;because after it each no. is multiple of 12(4*3)]
so remainder is equal to starting 3 no. sum
remainder is9
[so their sum is alsoo divisible by 12 ;because after it each no. is multiple of 12(4*3)]
so remainder is equal to starting 3 no. sum
remainder is9
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