Question

what is the remainder when (11¹¹+22²²+33³³) is divisible by 10​?​

Answer 1

Answer:

So, the remainder when (11¹¹+22²²+33³³) is divided by 10 is 4.

Step-by-step explanation:

To find the remainder when (11¹¹+22²²+33³³) is divided by 10, we just need to find the last digit of each term and add them up.

The last digit of 11¹¹ is 1, because 11 to any power always ends in 1.

The last digit of 22²² is 6, because 2 to any even power always ends in 6.

The last digit of 33³³ can be found by looking at the pattern of the last digits of powers of 3: 3¹ = 3, 3² = 9, 3³ = 27, 3⁴ = 81. The last digit of the powers of 3 repeat in a pattern of 4: 3, 9, 7, 1. So, the last digit of 33³³ is the same as the last digit of 3³³, which is 7.

Therefore, the sum of the last digits is 1+6+7=14. The remainder when 14 is divided by 10 is 4.

So, the remainder when (11¹¹+22²²+33³³) is divided by 10 is 4.

To know more about the remainder refer:

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