Question

what is the remainder when (17^29+19^29) is divided by 18?​

Answer 1

remainder is 0

Step-by-step explanation:

queficiant is 1044 and 1044 is multiple of 18 so remainder is 0

Answer 2

Answer:

0

Step-by-step explanation:

17²⁹/18 = (18 - 1)²⁹ / 18

Now as per Bernoulli therorm, all the terms  (18 - 1)²⁹ will be multiple of 18 apart from last term (-1)²⁹. -1/18 = Remainder as 17.

19²⁹/18 = (18 + 1)²⁹ / 18

Now as per Bernoulli therorm, all the terms  (18 + 1)²⁹ will be multiple of 18 apart from last term (1)²⁹. 1/18 = Remainder as 1.

17+  1 = 18. So there is no remainder left. Remainder = 0