what is the remainder when (2*3*4*2007*2008*2009)-2008 is divided by 2009 ??
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Answer:
The answer is 96721343.000497
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Concept:
Prime Factor method
Step-by-step explanation:
- By the smallest prime number, divide the supplied number. In this instance, the integer should be divided exactly by the smallest prime number.
- Divide the quotient once again by the smallest prime.
- Continue doing this until the quotient is 1.
Since 2009 is a factor in the first term, it is obvious that it is divisible by 2009.
The current second term 2008 would be the answer if the second term was positive, but keep in mind that the final term is always positive.
We, therefore, write -2008 as -2009+1.
The second term is currently divided by 2009
Our response is the third positive word that is smaller than 2009, which is 1.
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