Question

What is the remainder when 2^41 is divided by 127?​

Answer 1

Answer:

good afternoon yaar

I can't solve it

Answer 2

Answer:

64

Step-by-step explanation:

$2^{41}$/127 =$(2^{7}) ^5$ * $2^{6}$

Remainder when  $(2^{7}) ^5$ is divided by 127 = 1;  

Since $2^{7}$ mod 127 = 1

Remainder when $2^{6}$  is divided by 127 = 64

Required remainder = 1 × 64 = 64.