What is the remainder when 2222^5555 is divided by 7?
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Answer:
2222=3mod(7)
3^3=(-1)mod(7)
3^(3×1851)=(-1)mod(7)
3^5555=(-9)mod(7)
3^5555=(-2)mod(7)
3^5555=5mod(7)
Therefore remainder when 2222^5555 divided by 7 is 5.
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