What is the remainder when (2x^+3x+7) is divided by (x-2)
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Answer:
x-2= 0
x = 2
2x^2 +3x +7
2(2)^2 + 3(2) +7
8+6+7 = 21
so , 21 is remainder.
Answered by
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let p(x) = 2x^2 +3x+7
and g(x) = x-2
By the remainder theorem if p(x) is divided by g (x) then the remainder is
p(2) = 2(2)^2+3(2)+7
= 8+13=21
please see the figure carefully...and mark it as brainleast answer...
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