What is the remainder when ((4^428)+3) is divided by 6.
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Answered by
0
Answer:
let solve it with an example
4^2=16 when divided by 6 , R= 4
4^3= 64 when divided by 6 , R=4
similarly when 4^428 is divided by 6 remainder= 4
now, 4^428+3/6, R= 4+3 = 7 and 7 is larger than 6
so , 7÷6, R=1
so, R=1. Hope it helps uu☺️
Answered by
0
Answer:
R= 1
Explanation:
Example :- 4^2 =16 when divided by 6,
R = 4
4^3 = 64 when divided by 6, R = 4
Similarly when 4^428 ia divided by 6 remainder= 4
now, 4^428+3/6, R= 4+3 = 7 and 7 is larger than 6.
So, 7÷6, R=1
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