Math, asked by naskaraditya19, 2 months ago

What is the remainder when ((4^428)+3) is divided by 6.​

Answers

Answered by jitenderjakhar
0

Answer:

let solve it with an example

4^2=16 when divided by 6 , R= 4

4^3= 64 when divided by 6 , R=4

similarly when 4^428 is divided by 6 remainder= 4

now, 4^428+3/6, R= 4+3 = 7 and 7 is larger than 6

so , 7÷6, R=1

so, R=1. Hope it helps uu☺️

Answered by rishabh201821
0

Answer:

R= 1

Explanation:

Example :- 4^2 =16 when divided by 6,

R = 4

4^3 = 64 when divided by 6, R = 4

Similarly when 4^428 ia divided by 6 remainder= 4

now, 4^428+3/6, R= 4+3 = 7 and 7 is larger than 6.

So, 7÷6, R=1

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