what is the remainder when 4^96 is divided by 6
Answers
Answered by
7
When 4^1 = 4 divided by 6, the remainder is 4.
When 4^2 = 16 divided by 6, the remainder is 4.
When 4^3 = 64 divided by 6, the remainder is 4.
Likewise, when 4^96 divided by 6, the remainder is 4.
Hope this helps@
When 4^2 = 16 divided by 6, the remainder is 4.
When 4^3 = 64 divided by 6, the remainder is 4.
Likewise, when 4^96 divided by 6, the remainder is 4.
Hope this helps@
Answered by
0
By applying the rule of common factors,
R[4^96/6]
=R[(2^192/2×3)]
=2×R[2^191/3]
By applying binomial theorem,
R[(2^191/3)]
=R{[(3-1)^191]/3}
=(-1)^191
=(-1) or 2
So, R[(4^96)/6]= 2×R[(2^191)/3]= 4
Hope this helps you!! :)
R[4^96/6]
=R[(2^192/2×3)]
=2×R[2^191/3]
By applying binomial theorem,
R[(2^191/3)]
=R{[(3-1)^191]/3}
=(-1)^191
=(-1) or 2
So, R[(4^96)/6]= 2×R[(2^191)/3]= 4
Hope this helps you!! :)
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