Question

what is the remainder when (54^3+ 3^54 +354) is divided by 2

Answer 1

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Answer: 79147.5

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Step-by-step explanation:

=54^×3+3^×54+345 ÷ 2

=157464+486+345 ÷2

=158295÷2

=79147.5

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Answer 2

Given: $\[{54^3} + {3^2} \times 54 + 354\]$.

To find the remainder if the given number is divided by 2.

Solution:

Simplify.

$\[\begin{array}{l}{54^3} + {3^2} \times 54 + 354\\ = 157464 + 486 + 354\\ = 158304\end{array}\]$

Understand that there will no remainder when the given number is divided by 2 as the unit digit of the number is an even number.

Therefore,

the remainder when $\[{54^3} + {3^2} \times 54 + 354\]$ is divided by 2 is 0.