What is the remainder when 91+92+93+....+98is divided by 6?
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For such problems remainders of individual dividends can be added to find final reminder
i.e remainders of 91,92,.....,98 when divided by 6 are 1,2,3,4,5,0,1 and 2
Now problem simplifies to remainder of (1+2+3+4+5+0+1+2)/6 = 18/6 which is 0
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Answer this question is 46
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