what is the remainder when the number 101102103104105106107...14811449150 is divided by 9?
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2
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What is the remainder when the number 101102103104105106107...14811449150 is divided by 9?
A number is divisible by 9 if sum of digits of number is divisible by 9
Sum of Digits of
101102103104105106107...14811449150
100's digit = 1 (50 times)
10's Digits = 10 * (1 + 2 + 3 + 4) + 5
Unit's Digit = 5*(1 + 2 + 3 +...........................+7+8+9)
Sum of Digits = 50 * 1 + 10 * (1 + 2 + 3 + 4 ) + 5 + 5*(1 + 2 + 3 +...........................+7+8+9)
= 50 + 10 * 4 * 5/2 + 5 + 5 * 9 * 10/2
= 50 + 100 + 5 + 225
= 380
380/9 = 42*9 + 2
so remainder will be 2
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