Question

What is the remainder when the number 101102103104105106107....148149150 is divided by 9?

Answer 1

Answer:

2

Step-by-step explanation:

Given  

What is the remainder when the number 101102103104105106107....148149150 is divided by 9?

We know that

Test of divisibility for 9 will be sum of digits should be divisible by 9.

So we have sum of digits in hundred’s place, tenth’s place and units place.

Sum of digits in hundred’s place will be that is 101,102…………150 is  

1 x 50 = 50

Sum of digit’s in tens place will be

0 x 9 + 1 x 10 + 2 x 10 + 3 x 10 + 4 x 10 + 5 x 1 = 105

Sum of digit’s in units place will be 5 x (1 + 2 + 3 + 5 + 6 + + 8 + 9) = 225

So total will be 105 + 225 + 50 = 380

Now remainder will be 380 / 9 = 2