what is the remainder when we Divide 112 by 119 342
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If a number N, divided by a divisor D, yields a quotient Q, with a remainder R, then
N=D×Q + R , and vice versa.
So in this case, the number N is
N=114×Q + 21. We do not know N or Q, but we know that
114=19×6, so we can write
N=(19×6)×Q + 21,
N=19×(6×Q) + 21
N=19×(6×Q) + 19 + 2
N=19x(6×Q+1) + 2
That last expression says that the number N, when divided by 19, yields a quotient of 6×Q+1, with a remainder of 2.
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