Question

what is the remainder, when x^3+3x^2+4z+6 is divided by x +3?

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Answer 1

Correct Question :-

• What is the remainder, when x³+ 3x²+ 4x + 6 is divided by x + 3?

Answer :-

• Remainder = 0

Given :-

• Divisor = x + 3
• Dividend = x³+ 3x²+ 4x + 6

To Find :-

• Remainder = ?

Explanation :-

Let us first find the value of 'x' in divisor,

$\rm : \; \mapsto x+3 = 0$

$\rm : \; \mapsto x = 0-3$

$\green { \bf : \; \mapsto x = -3 \qquad \star}$

Now substituting the value of 'x' in dividend,

$\rm : \; \mapsto \; \; p(x) = x^3+3x^2+4x+6$

$\rm : \; \mapsto \; \; p(-3) = (-3)^3+3(-3)^2+4(-3)+6$

$\rm : \; \mapsto \; \; = (-3)+3(3)+(-12)+6$

$\rm : \; \mapsto \; \; = -3+9-12 +6$

$\rm : \; \mapsto \; \; = 9+6-3-12$

$\rm : \; \mapsto \; \; = 15-15$

$\blue { \underline { \boxed { \bf : \; \mapsto \; \; = 0 }}}$

Hence, the remainder when x³+ 3x²+ 4x + 6 is divided by x + 3 is 0.