Question

what is the remainder when (x^3+6x^2_4x+2)ia divided by (x_3)​

Answer 1

Answer:

Here's your answer......

Answer 2

Answer:

$\huge{\boxed{\rm{\red{Remainder=71}}}}$

Step-by-step explanation:

Given polynomial=p(x)=x³+6x²-4x+2

Given divisor=x-3

We know that If p(x) is divided by (x-a) then the remainder is p(a).

Given p(x) is divided by x-3 then the remainder is p(3)

=>p(3)=(3)³+6(3)²-4(3)+2

=>p(3)=27+6(9)-12+2

=>p(3)=27+54-12+2

=>p(3)=83-12

=>p(3)=71

Remainder is 71

Remainder theorem:-

Let p(x) be a polynomial of degree greater than or equal to 1 and x-a is another linear polynomial then it p(x) is divided by x-a then the remainder is p (a).