Question

What is the remainder when x^4+4x^3-5x^2-6x-+7 is divided by x-3

Answer 1

Answer:

theorem:- let p(x) be a polynomial and (x-a) be another polynomial of degree less than p(x) so if p(x) is divided by (x-a) the remainder will be

p(a)

Given question:-

p(x)=x^4+4x^3-5x^2-6x+7

g(x)=x-3

So when p(x) is divided by (x-3) the remainder will be p(3)=3^4+4×3^3-5×3^2-6×3+7

=81+108-45-18+7

=196-63

=133

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