What is the remainder when x^99 +99 is divided by x+1?
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Answered by
3
the required remainder is 0 .
Answered by
17
hey!!!
p(x) = x^99 + 99
g(x) = x + 1
>> x + 1 = 0
>> x = -1
on putting values :-
= (-1)^99 + 99
= -99 + 99
= 0
hence, remainder is 0
Cheers!!!
p(x) = x^99 + 99
g(x) = x + 1
>> x + 1 = 0
>> x = -1
on putting values :-
= (-1)^99 + 99
= -99 + 99
= 0
hence, remainder is 0
Cheers!!!
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