Question

what is the Remainder when (x raise to power 4 +1) is divided by (x-2)​

Answer 1

Answer:

Remainder = 17

Step-by-step explanation:

Let p(x)= x⁴+1

If p(x) divided by (x-2) then the remainder is p(2).

p(2)= 2⁴+1

= 16+1

= 17

Therefore,

Remainder = 17

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Answer 2

When  $(x^4+1)$ is divided by $(x-2)$ the remainder is 17.

Step-by-step explanation:

We need to find the remainder when $(x^4+1)$ is divided by $(x-2)$.

Let $f(x)=(x^4+1)$

and

$g(x)=(x-2)$

If g(x) = 0, x = 2

Now finding f(2)

$f(2)=(2^4+1)\\\\f(2)=17$

So, when  $(x^4+1)$ is divided by $(x-2)$ the remainder is 17.

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Division method

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