what is the remainder, when x2+3x2+4x+6 is divided by x+3?
Answers
Answer:
-6
Step-by-step explanation:
It will be easier to do this by remainder theorem and factor theorem,
REMAINDER THEOREM - When a polynomial f(x) is divided by (x-α), then the remainder is given by f(α)
FACTOR THEOREM - When a polynomial f(x) is divided by (x-α) such that (x-α) is its factor, then f(α)=0
Here, f(x) = x³+3x²+4x+6
and the divisor is given by (x+3)
now, x+3=0, x= -3
So, f(α)= (-3)³+3(-3)²+4(-3)+6 = -27+27-12+6 =-6
ans -6 is the remainder.
if u want, u can check it by long division method too
Answer:
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