Question

What is the resistance between A and B in the following circuit (Fig. 10.16)?
(a) 1 Ω
(b) 2 Ω
(c) ½ Ω
(d) 3/2 Ω​

Answer 1

Answer:

Explanation:

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To begin this question, let us start from the left. This also has a reason & quote, if nothing goes right go left!

We can see 1 ohm and 1 ohm in series. So it gets added.

1 + 1 = 2 ohm.

Now, 2 ohm and base triangle 2 ohm are in Parallel.

$\dfrac{1}{2}+ \dfrac{1}{2}$ = 1 ohm.

We get the total triangle resistance as 1 ohm.

Again, we can see 1 ohm and 1 ohm gets added in series, so we get 2 ohm.

And again 2 ohm are in parallel.

$\dfrac{1}{2}+ \dfrac{1}{2}$ = 1 ohm.

Again 1 ohm and 1 ohm gets added to form 2 ohm, 2 ohm again in parallel. Again total resistance is 1 ohm.

Thus in last Triangle also, we again add 1 ohm with 1 ohm and get 2 ohm. It is again in parallel with the base 2 ohm. So, we get

$\dfrac{1}{2}+ \dfrac{1}{2}$ = 1 ohm.

So, 1 ohm is the final answer.

Answer 2

Answer:

Solution :

Remember following formulae in order to solve such kind of circuit problems.

❇ Equivalent of series :

• R = R₁ + R₂ + ... + Rₙ

❇ Equivalent of parallel :

• 1/R = 1/R₁ + 1/R₂ + ... + 1/Rₙ

Now let's solve it step by step :)

In right part, two resistors of 2Ω and 2Ω respectively are connected in parallel.

⇒ 1/R₁ = 1/2 + 1/2

⇒ 1/R₁ = 2/2

⇒ R₁ = 1Ω

Thus in last Triangle also, we again add 1 ohm with 1 ohm and get 2 ohm. It is again in parallel with the base 2 ohm. So, we get

➛ 1/R = 1/2 + 1/2

➛ 1/R = 2/2

➛ R = 1Ω

Options a is Correct !