What is the resistance of a heating coil on an electric stove that has a current of 25 A flowing through it and uses 0.24 kV? Round to two significant digits (one decimal). *
Answers
Answer:
Given:
Voltage(V) = 220 Volts
Resistance of Coil A, Ra = 24 ohm
Resistance of Coil B, Rb = 24 ohm
Case I: When coils are used separately.
Applying the formula,
Ifbox[V = IR]V = IR
We get,
I = \frac[V][R]I=RV
I = \frac{220][24] = 9.17 Al=24220=9.17A Therefore, the current flowing in this circuit is 9.17 Amperes.
Case Il: When coils are used in series.
Equivalent Resistance,
R = 24 + 24 = 48 ohms Applying Formula V = IR,
I = \frac{VXR]=RV
= \frac{220}{48] = 4.58Al=48220=4.58A Therefore the current flowing is 4.58 Amperes.
Case III: When coils are used in parallel.
Equivalent Resistance,
R = \frac{R1R2][R1 + R2]R=R1+R2R1R2
R = \frac[24 * 24][24 + 24]R=24+2424*24
R = \frac{576][48] = 12
OhmsR=48576=120hms
Current Flowing,
I = \frac[V][R]I=RV
I = \frac{220][12] = 18.33Al=12220=18.33A
Therefore, the current flowing is 18.33 Amperes.