What is the resistance of a heating coil on an electric stove that has a current of 25 A flowing through it and uses 0.24 kV? Round to two significant digits (one decimal). *
Answers
Explanation:
Case I: 9.17 Amperes
Case II: 4.58 Amperes
Case III: 18.33 Amperes
Step-by-step explanation:
Given:
Voltage(V) = 220 Volts
Resistance of Coil A, Ra = 24 ohm
Resistance of Coil B, Rb = 24 ohm
Case I: When coils are used separately.
Applying the formula,
\fbox{V = IR}V = IR
We get,
I = \frac{V}{R}I=RV
I = \frac{220}{24} = 9.17 AI=24220=9.17A
Therefore, the current flowing in this circuit is 9.17 Amperes.
Case II: When coils are used in series.
Equivalent Resistance,
R = 24 + 24 = 48 ohms
Applying Formula V = IR,
I = \frac{V}{R}I=RV
I = \frac{220}{48} = 4.58AI=48220=4.58A
Therefore the current flowing is 4.58 Amperes.
Case III: When coils are used in parallel.
Equivalent Resistance,
R = \frac{R1R2}{R1 + R2}R=R1+R2R1R2
R = \frac{24 * 24}{24 + 24}R=24+2424∗24
R = \frac{576}{48} = 12 OhmsR=48576=12Ohms
Current Flowing,
I = \frac{V}{R}I=RV
I = \frac{220}{12} = 18.33AI=12220=18.33A
Therefore, the current flowing is 18.33 Amperes.