Question

what is the resistance of a light bulbs that carries a current of 2.5 ampere at a potential difference of 12 volt​

Answer 1

Answer:

❗ Hllw ❗

Explanation:

$i = 2.5a \\ v = 12v \\ r = \frac{v}{i} \\ = > \frac{12}{2.5} \\ = > r = 4.8 \: ohm$

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Answer 2

Answer:I=2.5A

V=12VOLT

THEREFORE,

R=V/I

R=120/25

R=4.5 OHM

Explanation: