what is the resistance of the filament of 200 voltage,,,100 Watt lamp?
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Explanation:
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Given that the power of bulb is 100W and operated at 200V potential difference.
We are all familiar with the formula i.e P=VI according to the given problem P=100W & V=200V. substituting in the above formula we get i=0.5 amp.
We also known that P=i^2R. substituting the required values in equation above, we get R as R=100/(0.5)×(0.5) i.e.R=10000/25 =400 ohm
Hence the resistance offered by the bulb is 400ohm
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Answered by
1
Answer:
ANS: 400 ohm
Explanation:
P=V/I
100=200/I
I=O.5 Ampere
R=V/I
R= 200/ 0.5
ohm
R= 400
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