What is the result stored in x, after evaluating the following expression?
int x = 7;
x = x++ * 2+ 3 * - - x;
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x++ =5 so..
5*2 = 10
(x=6 here the increment happends after the value is used)
3*5 ➡(1 is taken from x first before the value is used this is why its 5 again)
5*2 = 10
3*5 = 15
x = 25
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