Question

What is the resultant of three coplanar forces, 30N at 0°, 40N at 30°, 40N at 150° ?

Answer 1

Along horizontal
Fx = 30 + 40Cos30 - 40Sin60
= 30 + 20√3 - 20√3
= 30 N

Along vertical
Fy = 0 + 40Sin30 + 40Cos60
= 20 + 20
= 40

Resultant force = √(Fx² + Fy²)
= √(30² + 40²)
= 50 N
Magnitude of Resultant force is 50 N

Tanθ = Fx / Fy
= 30 / 40
= 3 / 4
θ = 37°
Direction of resultant force is 37° with horizontal