what is the resultant resistance of the given figure below:
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4.5 Ω
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Answer: R= 4.5Ω
Explanation:
R1+R2 = 3Ω+6Ω = 9Ω
R3+R4 = 6Ω+3Ω = 9Ω
Now adding the new resistance in parallel
1/R = 1/ R1 + 1/ R2
1/R = 1/9Ω + 1/9Ω = 2/9Ω
R= 9/2Ω=4.5Ω
ε = I + (R+r)
36 = I + 4.5
36 - 4.5 =I
31.5 A = I
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