Physics, asked by cbnayana, 1 month ago

what is the resultant resistance of the given figure below:
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Answered by nihanthyepuri9
1

4.5 Ω

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Answered by niharasajeev
1

Answer: R= 4.5Ω

Explanation:

R1+R2 = 3Ω+6Ω = 9Ω

R3+R4 = 6Ω+3Ω = 9Ω

Now adding the new resistance in parallel

1/R = 1/ R1 + 1/ R2

1/R = 1/9Ω + 1/9Ω = 2/9Ω

  R= 9/2Ω=4.5Ω

ε = I + (R+r)

36 = I + 4.5

36 - 4.5 =I

31.5 A = I

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